Optimal. Leaf size=279 \[ \frac{i \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,-\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{a^2 c x^2+c}}-\frac{i \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{a^2 c x^2+c}}-\frac{11 a x}{9 c^2 \sqrt{a^2 c x^2+c}}+\frac{\tan ^{-1}(a x)}{c^2 \sqrt{a^2 c x^2+c}}-\frac{2 \sqrt{a^2 x^2+1} \tan ^{-1}(a x) \tanh ^{-1}\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{a^2 c x^2+c}}-\frac{a x}{9 c \left (a^2 c x^2+c\right )^{3/2}}+\frac{\tan ^{-1}(a x)}{3 c \left (a^2 c x^2+c\right )^{3/2}} \]
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Rubi [A] time = 0.430169, antiderivative size = 279, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 6, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.273, Rules used = {4966, 4958, 4954, 4930, 191, 192} \[ \frac{i \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,-\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{a^2 c x^2+c}}-\frac{i \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{a^2 c x^2+c}}-\frac{11 a x}{9 c^2 \sqrt{a^2 c x^2+c}}+\frac{\tan ^{-1}(a x)}{c^2 \sqrt{a^2 c x^2+c}}-\frac{2 \sqrt{a^2 x^2+1} \tan ^{-1}(a x) \tanh ^{-1}\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{a^2 c x^2+c}}-\frac{a x}{9 c \left (a^2 c x^2+c\right )^{3/2}}+\frac{\tan ^{-1}(a x)}{3 c \left (a^2 c x^2+c\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 4966
Rule 4958
Rule 4954
Rule 4930
Rule 191
Rule 192
Rubi steps
\begin{align*} \int \frac{\tan ^{-1}(a x)}{x \left (c+a^2 c x^2\right )^{5/2}} \, dx &=-\left (a^2 \int \frac{x \tan ^{-1}(a x)}{\left (c+a^2 c x^2\right )^{5/2}} \, dx\right )+\frac{\int \frac{\tan ^{-1}(a x)}{x \left (c+a^2 c x^2\right )^{3/2}} \, dx}{c}\\ &=\frac{\tan ^{-1}(a x)}{3 c \left (c+a^2 c x^2\right )^{3/2}}-\frac{1}{3} a \int \frac{1}{\left (c+a^2 c x^2\right )^{5/2}} \, dx+\frac{\int \frac{\tan ^{-1}(a x)}{x \sqrt{c+a^2 c x^2}} \, dx}{c^2}-\frac{a^2 \int \frac{x \tan ^{-1}(a x)}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{c}\\ &=-\frac{a x}{9 c \left (c+a^2 c x^2\right )^{3/2}}+\frac{\tan ^{-1}(a x)}{3 c \left (c+a^2 c x^2\right )^{3/2}}+\frac{\tan ^{-1}(a x)}{c^2 \sqrt{c+a^2 c x^2}}-\frac{(2 a) \int \frac{1}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{9 c}-\frac{a \int \frac{1}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{c}+\frac{\sqrt{1+a^2 x^2} \int \frac{\tan ^{-1}(a x)}{x \sqrt{1+a^2 x^2}} \, dx}{c^2 \sqrt{c+a^2 c x^2}}\\ &=-\frac{a x}{9 c \left (c+a^2 c x^2\right )^{3/2}}-\frac{11 a x}{9 c^2 \sqrt{c+a^2 c x^2}}+\frac{\tan ^{-1}(a x)}{3 c \left (c+a^2 c x^2\right )^{3/2}}+\frac{\tan ^{-1}(a x)}{c^2 \sqrt{c+a^2 c x^2}}-\frac{2 \sqrt{1+a^2 x^2} \tan ^{-1}(a x) \tanh ^{-1}\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{c+a^2 c x^2}}+\frac{i \sqrt{1+a^2 x^2} \text{Li}_2\left (-\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{c+a^2 c x^2}}-\frac{i \sqrt{1+a^2 x^2} \text{Li}_2\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{c^2 \sqrt{c+a^2 c x^2}}\\ \end{align*}
Mathematica [A] time = 0.366334, size = 168, normalized size = 0.6 \[ \frac{\left (a^2 x^2+1\right )^{3/2} \left (36 i \text{PolyLog}\left (2,-e^{i \tan ^{-1}(a x)}\right )-36 i \text{PolyLog}\left (2,e^{i \tan ^{-1}(a x)}\right )-\frac{45 a x}{\sqrt{a^2 x^2+1}}+\frac{45 \tan ^{-1}(a x)}{\sqrt{a^2 x^2+1}}+36 \tan ^{-1}(a x) \log \left (1-e^{i \tan ^{-1}(a x)}\right )-36 \tan ^{-1}(a x) \log \left (1+e^{i \tan ^{-1}(a x)}\right )-\sin \left (3 \tan ^{-1}(a x)\right )+3 \tan ^{-1}(a x) \cos \left (3 \tan ^{-1}(a x)\right )\right )}{36 c \left (c \left (a^2 x^2+1\right )\right )^{3/2}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.323, size = 370, normalized size = 1.3 \begin{align*} -{\frac{ \left ( i+3\,\arctan \left ( ax \right ) \right ) \left ( i{x}^{3}{a}^{3}+3\,{a}^{2}{x}^{2}-3\,iax-1 \right ) }{72\, \left ({a}^{2}{x}^{2}+1 \right ) ^{2}{c}^{3}}\sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) }}+{\frac{ \left ( 5\,\arctan \left ( ax \right ) +5\,i \right ) \left ( 1+iax \right ) }{8\,{c}^{3} \left ({a}^{2}{x}^{2}+1 \right ) }\sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) }}-{\frac{ \left ( -5+5\,iax \right ) \left ( \arctan \left ( ax \right ) -i \right ) }{8\,{c}^{3} \left ({a}^{2}{x}^{2}+1 \right ) }\sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) }}+{\frac{ \left ( i{x}^{3}{a}^{3}-3\,{a}^{2}{x}^{2}-3\,iax+1 \right ) \left ( -i+3\,\arctan \left ( ax \right ) \right ) }{72\,{c}^{3} \left ({a}^{4}{x}^{4}+2\,{a}^{2}{x}^{2}+1 \right ) }\sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) }}-{\frac{i}{{c}^{3}} \left ( i\arctan \left ( ax \right ) \ln \left ( 1-{(1+iax){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) -i\arctan \left ( ax \right ) \ln \left ( 1+{(1+iax){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) +{\it polylog} \left ( 2,{(1+iax){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) -{\it polylog} \left ( 2,-{(1+iax){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) \right ) \sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) }{\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{a^{2} c x^{2} + c} \arctan \left (a x\right )}{a^{6} c^{3} x^{7} + 3 \, a^{4} c^{3} x^{5} + 3 \, a^{2} c^{3} x^{3} + c^{3} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\arctan \left (a x\right )}{{\left (a^{2} c x^{2} + c\right )}^{\frac{5}{2}} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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